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awesome day yesterday. my hamstrings are wasted; which got me thinking: has anyone done the math on how much force is involved in kiting? riding over-powered feels a lot like pulling a heavy deadlift and i'm wondering what the equivalent amount of weight would be.
something like: kiting at X mph windspeed with a Y m2 kite = lifting Z pounds.
i suck at math; but i know we have some engineers on this forum. who has a formula for this?
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Were you riding a surfboard?
I blew out my hamstring real good last year just riding hard on my surfboard
Not that over powerd juat slashing around
last week I tweeked it again on the surfboard
I was very lit up on my 9m a couple weeks ago and blown off the water on my twin tip
And my hamsteing was just fine
so you might want to look into force of different boards?
someone should invent a force platform (http://en.wikipedia.org/wiki/Force_platform) that's waterproof, battery powered, and fits on the deck of a kiteboard.
"A ship is safe in harbor, but that's not what ships are built for"
Might be easier to put a force gauge on the lines.
This my guess for a 12m kite in 25mph wind seeing 50 mph apparent wind (wind + some % of kiter speed + some % of kite speed right before liftoff for a jump - I suspect this is high)
12 m2 kite
50 mph kite speed (25 mph wind + kite motion)
1.2 lift coef (high)
Lift - 1/2*air density*velocity*velocity*area*lift_coef = ~1000 lbf
you guys are doing too much thinking and not enough kiting
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Calculating force from your couch:
1) watch vid of someone boosting
2) dead reckon the mid-jump velocity
3) calculate acceleration a = dv/dt
4) dead reckon the weight, plug it all into F=ma
Special thanks to my high school physics teacher
Cdog - it may be time for you to do a little Yoga to get those hammies more flexible....
aging is so awesome - your muscles get more limber/stronger....recovery periods shorter....o2 processing capability goes up....
But you do appreciate things more.
Get sum, Z
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